CTET Notification 2019 – Central Teachers Eligibility Test July 2019

CTET Notification 2019

Central Board of Secondary Education (CBSE) of India released an official notification for Central Teachers Eligibility Test (CTET) 2019. Candidates who were waiting for this Teachers Eligibility Test are now able to submit their application through online application method after fulfilling below given eligibility criteria.

Related: CTET Result 2018

CTET Notification 2019 Details

Name of Examination: Central Teachers Eligibility Test 2019

Organization: Central Board of Secondary Education

CTET 2019 Minimum Education Qualification (Primary Level)

Any one of below given:

1. Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 2- year Diploma in Elementary Education (by whatever name known)
2. Senior Secondary (or its equivalent) with at least 45% marks and passed or appearing in final year of 2- year Diploma in Elementary Education (by whatever name known), in accordance with the NCTE (Recognition Norms and Procedure), Regulations, 2002.
3. Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year Bachelor of Elementary Education (B.EI.Ed).
4. Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 2- year Diploma in Education (Special Education)*.
5. “Graduation with at least 50% marks and Bachelor of Education (B.Ed).

CTET 2019 Minimum Education Qualification (Secondary Level)

Any one of below given:

1. Graduation and passed or appearing in final year of 2-year Diploma in Elementary Education (by whatever name known).
2. Graduation with at least 50% marks and passed or appearing in 1-year Bachelor in Education (B.Ed).
3. Graduation with at least 45% marks and passed or appearing in 1-year Bachelor in Education (B.Ed), in accordance with the NCTE (Recognition Norms and Procedure) Regulations issued from time to time in this regard.
4. Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year Bachelor in Elementary Education (B.EI.Ed).
5. Senior Secondary (or its equivalent) with at least 50% marks and passed or appearing in final year of 4- year B.A/B.Sc.Ed or B.A.Ed/B.Sc.Ed.
6. Graduation with at least 50% marks and passed or appearing in 1-year B.Ed. (Special Education).
7. Any candidate having qualified B.Ed. Programme recognized by the NCTE is eligible to appear in TET/CTET. Moreover, as per the existing TET guidelines circulated vide NCTE letter dated 11-02-2011, a person who is pursuing any of the teacher education courses (recognized by the NCTE or the RCI, as the case may be) specified in the NCTE Notification dated 23rd August 2010 is also qualified to appear in the TET/CTET.

Age Limit of CTET Notification 2019

Minimum age required to apply for this examination is 18 years.

Application Fee of CTET Notification 2019

Fee for single paper:

• General/ OBC – Rs. 700/-
• SC / ST / PH – Rs. 350/-

Fee for both papers:

• General/ OBC – Rs. 1200/-
• SC / ST / PH – Rs. 600/-

Candidate can pay the examination fee through online by using credit card/ debit card/ net banking or also can pay through E-Challan.

How to apply CTET July 2019

Candidates who are interested and successfully fulfilled above mentioned eligibility criteria are now able to submit their application through online portal. Online application link of CTET 2019 is below given and candidates need to complete all procedure before last date.

Important Dates of CTET Notification 2019

• Starting Date of Online Application: 5th February 2019
• Last Date of Online Application: 8th March 2019
• Last Date for Payment of Application Fee: 8th March 2019
• Date of Online Application Correction: 14th to 20th March 2019
• Date of CTET Examination: 7th July 2019

Important Web Links of CTET Notification 2019